Timeline for "Threaded" Truncated Icosahedon
Current License: CC BY-SA 2.5
5 events
| when toggle format | what | by | license | comment | |
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| Jun 5, 2010 at 13:17 | comment | added | Steve Huntsman | @John--Seems like the desired Eulerian path should be a sort of "double cover" Hamiltonian path, similar in spirit to a de Bruijn sequence. | |
| Jun 5, 2010 at 3:20 | history | edited | Kristal Cantwell | CC BY-SA 2.5 |
addition of material
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| Jun 5, 2010 at 2:56 | comment | added | John Stillwell | If you are willing to have two threads in each tube, but six at each vertex, then you can do it with one knot. The reason is that, when you double each edge of the graph, each vertex becomes of even degree, hence there is an Eulerian closed path. | |
| Jun 4, 2010 at 23:00 | comment | added | cartesys | I am well aware of the metric properties of the truncated icosahedon. I rephrase my question. Given 90 idetical pieces of tubing and some length(s) of string, how can I build from these a truncated icosahedron knowing that each piece of tubing contains at most 2 threads of string, that there should be no more than three threads at each vertex (or node) and altogether the fewer number of knots (possibly only one). Thank you. | |
| Jun 4, 2010 at 21:11 | history | answered | Kristal Cantwell | CC BY-SA 2.5 |