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May 27, 2017 at 10:44 vote accept Vanessa
May 27, 2017 at 10:11 answer added fedja timeline score: 2
May 27, 2017 at 9:00 history edited Vanessa CC BY-SA 3.0
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May 27, 2017 at 8:49 history edited Vanessa CC BY-SA 3.0
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May 27, 2017 at 8:48 comment added Vanessa @RW Yes, exactly.
May 27, 2017 at 8:39 comment added R W @Squark I presume you are talking about increasing filtrations, so that in the case when $\mathcal F_n$ correspond to finite partitions these partitions are becoming finer as $n$ grows - right?
May 27, 2017 at 8:35 comment added R W @Henry.L I am curious - what are the slightly different definitions of push-forward measures in probability you are referring to?
May 27, 2017 at 7:53 history edited Vanessa CC BY-SA 3.0
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May 27, 2017 at 7:43 comment added Vanessa @fedja, Henry.L : I added some clarifications, I hope this helps? Please tell me if the question is still unclear.
May 27, 2017 at 7:40 history edited Vanessa CC BY-SA 3.0
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May 27, 2017 at 0:52 comment added Henry.L @fedja I totally agree. $D_{KL}$ is easier to decode, it is the KL divergence between two prob. measures. For the push-forward, there are two slightly different definition in probability afaik, so there is definitely such a need to clarify notations.
May 26, 2017 at 21:56 comment added fedja Sorry, I meant $\mathcal P(A\cap \{X=X(\omega)\})/\mathcal P(\{X=X(\omega)\})$, of course. You see now to what extent one can get confused if you use too much of a special language and assume that people understand it ;-).
May 26, 2017 at 21:28 comment added fedja Could you, please, remind the definition of $D_{KL}$? I should confess that I'm totally ignorant of this notation and I suspect that I'm not alone :-) Also, do I understand it right that $Q_n(\omega)(A)=\mathcal P(A\cap \{X=X(\omega)\})$ (I'm used to the definitions that require $Q_n:\mathbb N\to \mathcal P(\Omega)$, so I feel a bit confused about the language)
May 26, 2017 at 17:53 history asked Vanessa CC BY-SA 3.0