Timeline for Strichartz estimates for the heat equation
Current License: CC BY-SA 3.0
6 events
when toggle format | what | by | license | comment | |
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May 23, 2017 at 20:18 | comment | added | Piero D'Ancona | That's what I said. Inhomogeneous Strichartz takes you to $L^1L^2$ which is estimated by $L^\infty L^2$. But of course the constant in this inequality is unbounded as $T\to \infty$ (it is exactly $T$) | |
May 23, 2017 at 3:43 | comment | added | Capublanca | I understand the non homogeneous case, thank you. However i'm wonder if also the bound $\Vert e^{t\Delta}F(t,\cdot)\Vert_{L^sL^p}\lesssim \Vert F \Vert_{L^{\infty}L^2}$ is true, at least for finite time intervals and for $F\in\mathcal{C}(\mathbb{R}^+,L^2)$. | |
May 22, 2017 at 20:00 | comment | added | Piero D'Ancona | You mean the non homogeneous equation $u_t-\Delta u=F$? you certainly can apply non homogeneous Strichartz estimates, so $u$ in $L^pL^q$ is estimated by $F$ in $L^1L^2$. For bounded intervals this is controlled by $L^\infty L^2$. | |
May 22, 2017 at 13:19 | vote | accept | Capublanca | ||
May 22, 2017 at 13:18 | comment | added | Capublanca | Thank you very much Piero! I have another doubt: is it also true that $e^{t\Delta}$ maps continuosly $L^{\infty}((0,T),L^2(\mathbb{R}^3))$ into $L^{s}((0,T),L^p(\mathbb{R}^3))$? For the Schrodinger flow it should not be true, but maybe it works in the heat case. | |
May 22, 2017 at 10:52 | history | answered | Piero D'Ancona | CC BY-SA 3.0 |