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Jun 4, 2010 at 12:24 vote accept Jamie Vicary
Jun 4, 2010 at 10:53 comment added Robin Chapman If you really want a presentation: generators $a$, $b$, $c$, $d$, $x$. Let $a^2=\cdots=d^2=x^{15}=1$, $a,\ldots,d$ commute, $xax^{-1}=b$, $xbx^{-1}=c$, $xcx^{-1}=d$, $xdx^{-1}=ab$.
Jun 4, 2010 at 10:42 comment added Jamie Vicary Thanks Robin! That's neat. Could you give me a presentation of that group so that I can play with this example myself?
Jun 4, 2010 at 10:08 history answered Robin Chapman CC BY-SA 2.5