Timeline for Determining conjugacy class of a subgroup from intersection with conjugacy classes
Current License: CC BY-SA 2.5
4 events
when toggle format | what | by | license | comment | |
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Jun 4, 2010 at 12:24 | vote | accept | Jamie Vicary | ||
Jun 4, 2010 at 10:53 | comment | added | Robin Chapman | If you really want a presentation: generators $a$, $b$, $c$, $d$, $x$. Let $a^2=\cdots=d^2=x^{15}=1$, $a,\ldots,d$ commute, $xax^{-1}=b$, $xbx^{-1}=c$, $xcx^{-1}=d$, $xdx^{-1}=ab$. | |
Jun 4, 2010 at 10:42 | comment | added | Jamie Vicary | Thanks Robin! That's neat. Could you give me a presentation of that group so that I can play with this example myself? | |
Jun 4, 2010 at 10:08 | history | answered | Robin Chapman | CC BY-SA 2.5 |