Timeline for Is the triple product in a Freudenthal triple system fully symmetric?
Current License: CC BY-SA 3.0
5 events
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| Jun 19, 2017 at 10:39 | comment | added | Vincent | For the sake of completeness: my speculation about Faulkner's $Q$ in the comment above is wrong. Faulkner's $Q$ is not totally symmetric in the special case of $E_7$, instead it is a slightly different $Q$ than the one from Ferrar/Helenius - see the details in my answer below. | |
| May 21, 2017 at 15:20 | comment | added | Vincent | Also Thank You to the anonymous MSE moderator who moved my question here! | |
| May 21, 2017 at 15:09 | vote | accept | Vincent | ||
| May 21, 2017 at 15:07 | comment | added | Vincent | That does indeed solve the mystery! I didn't say in detail how $Q$ is obtained from $q$ because the article I was quoting doesn't, I just copied their text (as far as copying from pdf is possible at all). The only mystery that remains is how the constructions of Ferrar and Helenius relate to those of Faulkner who claims that $Q$ only satifies your identity when $\sigma$ lies in some Klein four subgroup of $S_4$. But it might well be that Faulkners $Q$ becomes totally symmetric in the special case of $E_7$ - I'll try to figure that out myself and perhaps ask a follow up question. Thank you! | |
| May 21, 2017 at 13:17 | history | answered | John Baez | CC BY-SA 3.0 |