Timeline for Maximizing a ratio of determinants
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| May 20, 2017 at 5:57 | vote | accept | Ludwig | ||
| May 19, 2017 at 21:10 | answer | added | fedja | timeline score: 6 | |
| May 19, 2017 at 13:24 | comment | added | Ludwig | Yes. Sorry, but in my previous answer I meant $A$'s positive semidefinite with $\mathrm{tr}(A)\leq 1$. | |
| May 19, 2017 at 13:22 | history | edited | Ludwig | CC BY-SA 3.0 |
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| May 19, 2017 at 12:38 | comment | added | martin cripps | Maybe edit the question then to make this clear? | |
| May 19, 2017 at 11:54 | comment | added | Ludwig | @martincripps: $A$ must be symmetric positive definite and such that $\mathrm{tr}(A)=1$. | |
| May 19, 2017 at 11:40 | comment | added | martin cripps | Suppose $A$ has only two non-zero elements, $a_{12}$ and $a_{21}$, satisfying $\alpha=a_{12}d_1$ and $\alpha=a_{21}d_2$ (where $D$ has $(d_1,d_2,\dots,d_n)$ on the diagonal), then isn't the bottom of this equal to zero? | |
| May 19, 2017 at 8:13 | history | edited | Ludwig | CC BY-SA 3.0 |
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| May 19, 2017 at 7:08 | history | asked | Ludwig | CC BY-SA 3.0 |