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May 16, 2017 at 15:51 comment added Nick L For this hypothesis let $f$ be the projection to the circle and $U$ an open disk of radius more than $1$ (minus the origin!).
May 16, 2017 at 15:22 comment added Curiosity So the second hypothesis beside that $f$ is non constant that is $U$ is bounded.
May 16, 2017 at 13:25 comment added Nick L Actually, I guess my guess is wrong for the reason that we can take $U$ with empty boundary. I mean, standard projection $\mathbb{R}^2 \rightarrow \mathbb{R}^1$ would have been an easier counter-example. (Maybe also could assume $U$ has non-empty boundary...).
May 16, 2017 at 12:56 history answered Nick L CC BY-SA 3.0