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May 18, 2017 at 17:07 history edited Rodrigo de Azevedo CC BY-SA 3.0
Removed incorrections
May 18, 2017 at 16:56 comment added Rodrigo de Azevedo @NoahStein Thanks for the correction. I will edit my answer and remove everything other than the SDP formulation. I will also ask the OP that your answer be accepted, rather than mine.
May 18, 2017 at 15:08 comment added Noah Stein If $b$ is not a scalar multiple of $a$, then $ba^T$ is not positive semidefinite. To see this let $c$ be such that $c^Ta$ and $c^Tb$ have opposite signs -- this just means picking a hyperplane so that $a$ is on one side and $b$ is on the other. Then $c^T(ba^T)c < 0$. (Personally I always take the definition of positive semidefiniteness to include symmetry by default.)
May 18, 2017 at 14:40 history edited Rodrigo de Azevedo CC BY-SA 3.0
Minor update
May 18, 2017 at 14:28 history edited Rodrigo de Azevedo CC BY-SA 3.0
Minor update
May 18, 2017 at 14:11 history edited Rodrigo de Azevedo CC BY-SA 3.0
Added a section
May 17, 2017 at 14:26 history edited Rodrigo de Azevedo CC BY-SA 3.0
Minor update
May 17, 2017 at 14:08 history edited Rodrigo de Azevedo CC BY-SA 3.0
Improved the answer
May 17, 2017 at 13:22 vote accept user402940
May 18, 2017 at 17:22
May 15, 2017 at 18:14 comment added user402940 So, you basically formulated it as a SDP problem. But can we have a precise solution to this problem in terms of $a$ and $b$ vectors ? Or is it not possible and we have to solve this problem numerically ?
May 15, 2017 at 17:02 history answered Rodrigo de Azevedo CC BY-SA 3.0