Timeline for Generating a finite group from elements in each conjugacy class
Current License: CC BY-SA 2.5
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 16, 2019 at 19:05 | comment | added | alpoge | Not sure why this question got resurrected but while it’s up here a negative answer follows from the class equation 1 = \sum_C 1/#|Z(C)| valid for all groups (C are the conjugacy classes and Z(C) is the centralizer of any element in the conjugacy class). When passing to such a subgroup the number of conjugacy classes goes up (here is where the hypothesis gets used), but the sizes of the centralizers go down. | |
| Apr 29, 2019 at 22:50 | review | Close votes | |||
| Apr 30, 2019 at 13:34 | |||||
| Nov 21, 2014 at 1:40 | answer | added | M. Farrokhi D. G. | timeline score: 0 | |
| May 2, 2012 at 23:22 | answer | added | Hugo Chapdelaine | timeline score: 3 | |
| Nov 30, 2011 at 8:04 | answer | added | DavidLHarden | timeline score: 0 | |
| Jun 4, 2010 at 8:30 | vote | accept | Jamie Vicary | ||
| Jun 4, 2010 at 0:21 | answer | added | David E Speyer | timeline score: 70 | |
| Jun 4, 2010 at 0:09 | answer | added | Steve D | timeline score: 12 | |
| Jun 4, 2010 at 0:05 | comment | added | Victor Protsak | I don't see why there should be a connection: it's certainly not the case for finite cyclic and finite dihedral subgroups of $SO(3)$. | |
| Jun 3, 2010 at 22:05 | comment | added | Jamie Vicary | Actually, I would guess that since $SO(3)$ has this property, it wouldn't be too hard to find a finite subgroup of $SO(3)$ which also does. | |
| Jun 3, 2010 at 21:59 | history | asked | Jamie Vicary | CC BY-SA 2.5 |