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Jun 3, 2010 at 20:40 comment added Mike Skirvin If $X/S$ is not smooth, it is common to consider the cotangent complex rather than $\Omega^1.$ This is a derived version of Kahler differentials that agrees with $\Omega^1$ if $X/S$ is smooth. You can then define the tangent complex to be the dual of the cotangent complex. On a ring theoretic level, this is related to what's known as Andre-Quillen (co)homology.
Jun 3, 2010 at 20:23 comment added Donu Arapura I think it's useful, but one has to be more careful with it.
Jun 3, 2010 at 20:07 comment added user2330 Yes, but, in the case $X/S$ not smooth, is $\Omega^1_{X/S}$ useful ?
Jun 3, 2010 at 19:36 comment added Mariano Suárez-Álvarez I wonder if there are useful conditions for $\Omega^1$ to be reflexive...
Jun 3, 2010 at 19:27 history answered Donu Arapura CC BY-SA 2.5