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May 10, 2017 at 19:04 comment added Mark Wildon On the plus side, if you find a way to prove this identity by an RSK-type correspondence, you'll have solved one of the main open problems in the character theory of the symmetric group.
May 9, 2017 at 21:11 vote accept andrewBee
May 9, 2017 at 21:11 comment added andrewBee Blerg, thanks everyone! I had looked at the exercises in EC2, but only the ones surrounding RSK stuffs. The answer is much worse than I hoped!
May 9, 2017 at 20:31 history edited Mark Wildon CC BY-SA 3.0
Dimension bound is needed to get a non-zero representation in second paragraph (not first)
May 9, 2017 at 20:31 comment added Per Alexandersson These coefficients are also known to be hard to compute, in the sense of #P-complete (up to conventions). The family of Kronecker coefficients contain the Littlewood-Richardson coefficients, which, in turn, contains the (skew) Koskta numbers.
May 9, 2017 at 20:04 history edited Mark Wildon CC BY-SA 3.0
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May 9, 2017 at 19:57 comment added Sam Hopkins For a reference, see Stanley's EC2, exercise 7.78(f).
May 9, 2017 at 19:53 history answered Mark Wildon CC BY-SA 3.0