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May 8, 2017 at 15:08 comment added Joe Silverman @Amin235 Good point, you're using the reciprocal polynomial, i.e., the "reciprocal" of a degree $d$ poly $f(x)$ is $x^df(1/x)$. So you've switched the roots with their reciprocals, and maybe (? I haven't checked) your Fibonacci $p$-step number is actually the reciprocal of the smallest root of the characteristic poly.
May 8, 2017 at 13:59 comment added Amin235 Excuse me Professor Silverman, I think If you multiplied by $x-1$, we get $x^{p+1}-2\,x^p+1$. If you like I edit my question to show that how can I obtained $x^{p+1}-2\,x+1$. If you have a time, I suggest to see this post, maybe you find it interesting. Thanks for answer.
May 8, 2017 at 13:13 history answered Joe Silverman CC BY-SA 3.0