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May 4, 2017 at 12:32 answer added David E Speyer timeline score: 6
May 4, 2017 at 11:53 history edited Ian Morris
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May 3, 2017 at 23:18 answer added Anthony Quas timeline score: 10
S May 3, 2017 at 23:15 history suggested jeq CC BY-SA 3.0
Corrected some English typos.
May 3, 2017 at 23:00 review Suggested edits
S May 3, 2017 at 23:15
May 3, 2017 at 22:45 comment added user78249 Not sure if this helps, but letting $h = 4x(1-x)$ and $g(x) = \sin(\pi x)$, the way I usually solve conjugation problems like this is working with a limit. (By conjugation I mean $f$ conjugates between $h$ and $g$.) So for instance, if we let $f(x) = \lim_{n\to\infty} g^{\circ -n}(h^{\circ n}(x))$, then trivially it will satisfy your equation. Sadly, it's tough to prove convergence, and I have no idea if it's injective, and I doubt it would work on the entire interval $(0,1)$. But since both functions are symmetric about $1/2$ and injective there, it may work on $(0,1/2)$.
May 3, 2017 at 22:02 history asked matematicaActiva CC BY-SA 3.0