Timeline for Degree of sum of algebraic numbers
Current License: CC BY-SA 2.5
3 events
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Nov 6, 2022 at 16:26 | comment | added | Jianing Song | It is worth noting that although $K(\alpha,\beta) \neq K(\alpha+\beta)$, $K(\alpha,\beta)/K$ is still simple extension: a proof can be found here ($\alpha$ and $\beta$ are both separable in this example). By the way, the minimal polynomial of $\alpha$ in $K(\alpha+\beta)$ is still $x^{p-1} - s$, and the minimal polynomial of $\beta$ in $K(\alpha+\beta)$ is $(\alpha+\beta-x)^{p-1} - s$. | |
May 14, 2012 at 0:40 | comment | added | Gerry Myerson | Note that this is an example, not a counterexample, if $p=2$. | |
Jun 3, 2010 at 0:01 | history | answered | David E Speyer | CC BY-SA 2.5 |