Timeline for Can a number be palindromic in more than 3 consecutive number bases?
Current License: CC BY-SA 4.0
36 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Feb 16, 2023 at 7:19 | history | edited | domotorp |
edited tags
|
|
Aug 20, 2019 at 22:48 | comment | added | Vepir | @GerryMyerson Regarding a relevant sequence, I think A279093 is updated with all known 3-palindromic solutions. | |
Aug 20, 2019 at 22:43 | comment | added | Gerry Myerson | Loosely related: oeis.org/A214425 | |
Aug 20, 2019 at 17:33 | history | edited | Vepir | CC BY-SA 4.0 |
added 500 characters in body
|
Aug 20, 2019 at 17:21 | history | edited | Vepir | CC BY-SA 4.0 |
awaken from long slumber on a quest for the impossible four-palidnrome
|
Aug 20, 2019 at 14:59 | comment | added | Vepir | @joro Update: Now it is known that the $3$ digit solution does not exist. I will have to update this post. | |
Dec 5, 2017 at 15:50 | history | edited | Vepir | CC BY-SA 3.0 |
clarifications
|
S Nov 13, 2017 at 19:57 | history | bounty ended | CommunityBot | ||
S Nov 13, 2017 at 19:57 | history | notice removed | CommunityBot | ||
Nov 12, 2017 at 12:55 | history | edited | Vepir | CC BY-SA 3.0 |
fixed repl link
|
Nov 12, 2017 at 12:47 | history | edited | Vepir | CC BY-SA 3.0 |
python code for 2*digits+1 examples, run online
|
Nov 9, 2017 at 13:40 | history | edited | Vepir | CC BY-SA 3.0 |
updated code link
|
Nov 7, 2017 at 20:10 | comment | added | Vepir | @JoseBrox If we have $n$ and $n+3$, and we also include either $n+1$ or $n+2$ and "observe almost palindromic in four consecutive", then surprisingly, only 3 digit palindromes seem to have a chance to be palindromic in four consecutive bases ~ Updated the question | |
Nov 7, 2017 at 20:06 | history | edited | Vepir | CC BY-SA 3.0 |
added 2209 characters in body
|
Nov 7, 2017 at 12:22 | comment | added | Jose Brox | @Vepir Yes, sorry, I meant $n$ and $n+3$. I was just trying to understand if the obstruction for the existence of consecutive palindromes for $k=4$ (in case it exists) is of an algebraic/number-theoretic nature or rather of an analytic/combinatoric nature (which is what the existence of examples for $n$ and $n+3$ suggests). | |
Nov 7, 2017 at 11:47 | comment | added | Vepir | @JoseBrox Why $n, n+4$? There are a lot of examples, smallest one being $7=111_2=11_6$. You can easily modify the linked python code to generate them. If you meant $n, n+3$ there are again a lot of examples, smallest being $31=11111_2=111_5$. I only found interesting the palindromes which share consecutive bases. Smallest example for $k=1,2,3,4,\dots$ consecutive bases: $3(=11_2), 10(=11_3=101_4),178(= 454_6 =343_7 = 262_8), ? (k=4)$... The solution for four is either very large or does not exist. | |
Nov 7, 2017 at 8:55 | comment | added | Jose Brox | @Vepir Do you know of any example of palindrome simultaneously for bases $n$ and $n+4$? | |
Nov 6, 2017 at 23:09 | history | edited | Vepir | CC BY-SA 3.0 |
typo
|
Nov 6, 2017 at 22:40 | history | edited | Vepir | CC BY-SA 3.0 |
deleted 101 characters in body; edited tags
|
Nov 6, 2017 at 22:29 | history | edited | Vepir | CC BY-SA 3.0 |
added 1600 characters in body; edited tags
|
S Nov 5, 2017 at 18:26 | history | bounty started | Vepir | ||
S Nov 5, 2017 at 18:26 | history | notice added | Vepir | Draw attention | |
Nov 5, 2017 at 17:44 | history | edited | Vepir | CC BY-SA 3.0 |
added 3263 characters in body
|
May 1, 2017 at 0:17 | comment | added | Zack Wolske | @joro: That doesn't seem to be proven. At MSE, Vepir searched up to $10^7$ and found a one parameter family which does not extend to $4$ bases, and a single sporadic example, but there is no proof these are the only $3$ digit solutions. | |
Apr 30, 2017 at 12:52 | comment | added | joro | Is it known that three digit solution doesn't exist? | |
Apr 30, 2017 at 12:44 | history | reopened |
R.P. joro François Brunault Franz Lemmermeyer Gerry Myerson |
||
Apr 30, 2017 at 11:58 | comment | added | Franz Lemmermeyer | This is perfectly tweetable mathematics and thus certainly not offtopic on mathovertweet. I vote Reopen | |
Apr 30, 2017 at 9:05 | review | Reopen votes | |||
Apr 30, 2017 at 12:46 | |||||
Apr 30, 2017 at 8:57 | history | edited | Vepir | CC BY-SA 3.0 |
added 21 characters in body
|
Apr 30, 2017 at 8:49 | history | edited | Vepir | CC BY-SA 3.0 |
deleted 211 characters in body; deleted 1 character in body; deleted 139 characters in body
|
Apr 30, 2017 at 8:16 | history | closed |
Andy Putman Michael Albanese Peter Humphries user21574 Dmitri Pavlov |
Not suitable for this site | |
Apr 30, 2017 at 7:02 | comment | added | Gerry Myerson | @Andy, the question was asked at m.se two weeks ago. If it hasn't been answered to Vepir's satisfaction, no reason why it shouldn't be posted here. And no reason why anyone here has to accept Vepir's suggestion to answer there. I'm sure that if someone posts an answer here, Vepir will survive the trauma. | |
Apr 29, 2017 at 18:03 | comment | added | Andy Putman | I voted to close. MO is not intended to advertise questions on math.se, so if you want answers there, you should just ask there. | |
Apr 29, 2017 at 16:20 | history | edited | Vepir | CC BY-SA 3.0 |
deleted 52 characters in body
|
Apr 29, 2017 at 16:02 | review | Close votes | |||
Apr 30, 2017 at 8:16 | |||||
Apr 29, 2017 at 15:32 | history | asked | Vepir | CC BY-SA 3.0 |