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Feb 16, 2023 at 7:19 history edited domotorp
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Aug 20, 2019 at 22:48 comment added Vepir @GerryMyerson Regarding a relevant sequence, I think A279093 is updated with all known 3-palindromic solutions.
Aug 20, 2019 at 22:43 comment added Gerry Myerson Loosely related: oeis.org/A214425
Aug 20, 2019 at 17:33 history edited Vepir CC BY-SA 4.0
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Aug 20, 2019 at 17:21 history edited Vepir CC BY-SA 4.0
awaken from long slumber on a quest for the impossible four-palidnrome
Aug 20, 2019 at 14:59 comment added Vepir @joro Update: Now it is known that the $3$ digit solution does not exist. I will have to update this post.
Dec 5, 2017 at 15:50 history edited Vepir CC BY-SA 3.0
clarifications
S Nov 13, 2017 at 19:57 history bounty ended CommunityBot
S Nov 13, 2017 at 19:57 history notice removed CommunityBot
Nov 12, 2017 at 12:55 history edited Vepir CC BY-SA 3.0
fixed repl link
Nov 12, 2017 at 12:47 history edited Vepir CC BY-SA 3.0
python code for 2*digits+1 examples, run online
Nov 9, 2017 at 13:40 history edited Vepir CC BY-SA 3.0
updated code link
Nov 7, 2017 at 20:10 comment added Vepir @JoseBrox If we have $n$ and $n+3$, and we also include either $n+1$ or $n+2$ and "observe almost palindromic in four consecutive", then surprisingly, only 3 digit palindromes seem to have a chance to be palindromic in four consecutive bases ~ Updated the question
Nov 7, 2017 at 20:06 history edited Vepir CC BY-SA 3.0
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Nov 7, 2017 at 12:22 comment added Jose Brox @Vepir Yes, sorry, I meant $n$ and $n+3$. I was just trying to understand if the obstruction for the existence of consecutive palindromes for $k=4$ (in case it exists) is of an algebraic/number-theoretic nature or rather of an analytic/combinatoric nature (which is what the existence of examples for $n$ and $n+3$ suggests).
Nov 7, 2017 at 11:47 comment added Vepir @JoseBrox Why $n, n+4$? There are a lot of examples, smallest one being $7=111_2=11_6$. You can easily modify the linked python code to generate them. If you meant $n, n+3$ there are again a lot of examples, smallest being $31=11111_2=111_5$. I only found interesting the palindromes which share consecutive bases. Smallest example for $k=1,2,3,4,\dots$ consecutive bases: $3(=11_2), 10(=11_3=101_4),178(= 454_6 =343_7 = 262_8), ? (k=4)$... The solution for four is either very large or does not exist.
Nov 7, 2017 at 8:55 comment added Jose Brox @Vepir Do you know of any example of palindrome simultaneously for bases $n$ and $n+4$?
Nov 6, 2017 at 23:09 history edited Vepir CC BY-SA 3.0
typo
Nov 6, 2017 at 22:40 history edited Vepir CC BY-SA 3.0
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Nov 6, 2017 at 22:29 history edited Vepir CC BY-SA 3.0
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S Nov 5, 2017 at 18:26 history bounty started Vepir
S Nov 5, 2017 at 18:26 history notice added Vepir Draw attention
Nov 5, 2017 at 17:44 history edited Vepir CC BY-SA 3.0
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May 1, 2017 at 0:17 comment added Zack Wolske @joro: That doesn't seem to be proven. At MSE, Vepir searched up to $10^7$ and found a one parameter family which does not extend to $4$ bases, and a single sporadic example, but there is no proof these are the only $3$ digit solutions.
Apr 30, 2017 at 12:52 comment added joro Is it known that three digit solution doesn't exist?
Apr 30, 2017 at 12:44 history reopened R.P.
joro
François Brunault
Franz Lemmermeyer
Gerry Myerson
Apr 30, 2017 at 11:58 comment added Franz Lemmermeyer This is perfectly tweetable mathematics and thus certainly not offtopic on mathovertweet. I vote Reopen
Apr 30, 2017 at 9:05 review Reopen votes
Apr 30, 2017 at 12:46
Apr 30, 2017 at 8:57 history edited Vepir CC BY-SA 3.0
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Apr 30, 2017 at 8:49 history edited Vepir CC BY-SA 3.0
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Apr 30, 2017 at 8:16 history closed Andy Putman
Michael Albanese
Peter Humphries
user21574
Dmitri Pavlov
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Apr 30, 2017 at 7:02 comment added Gerry Myerson @Andy, the question was asked at m.se two weeks ago. If it hasn't been answered to Vepir's satisfaction, no reason why it shouldn't be posted here. And no reason why anyone here has to accept Vepir's suggestion to answer there. I'm sure that if someone posts an answer here, Vepir will survive the trauma.
Apr 29, 2017 at 18:03 comment added Andy Putman I voted to close. MO is not intended to advertise questions on math.se, so if you want answers there, you should just ask there.
Apr 29, 2017 at 16:20 history edited Vepir CC BY-SA 3.0
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Apr 29, 2017 at 16:02 review Close votes
Apr 30, 2017 at 8:16
Apr 29, 2017 at 15:32 history asked Vepir CC BY-SA 3.0