Timeline for Fourier transform that is almost a brick wall - but why?
Current License: CC BY-SA 3.0
14 events
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| May 2, 2017 at 8:34 | comment | added | Carlo Beenakker | your $h(x)$ is even in $x$, so it's a cosine transform | |
| May 2, 2017 at 7:20 | comment | added | Nicki | Thanks a lot! But doesn't it play a role here how the Fourier transform is defined? You seem to do the cosine-transform, but I intended $$H(f) = \int_{-\infty}^{\infty} h(x)\exp(-2\pi i f x)\mathrm{d}x.$$ | |
| Apr 29, 2017 at 21:28 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Apr 29, 2017 at 20:55 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Apr 29, 2017 at 17:36 | comment | added | Christian Remling | If we only know the behavior of $|H_a|, |H_b|$ (and not of the functions themselves), we can't really conclude much about $|H_a * H_b|$. | |
| Apr 29, 2017 at 9:51 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Apr 29, 2017 at 9:45 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Apr 29, 2017 at 9:36 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Apr 29, 2017 at 9:16 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Apr 29, 2017 at 9:08 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Apr 29, 2017 at 9:08 | comment | added | Carlo Beenakker | it is flat within 1%, I've added a detailed plot to show that. | |
| Apr 29, 2017 at 6:17 | comment | added | Piero D'Ancona | From your graph it seems that $|H_{3/2}|$ is actually flat in the region $|f|\le1$. Can you confirm numerically? | |
| Apr 28, 2017 at 21:13 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Apr 28, 2017 at 21:00 | history | answered | Carlo Beenakker | CC BY-SA 3.0 |