Timeline for Gevrey estimate of derivatives
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 2, 2017 at 20:41 | comment | added | Bazin | Yes, you are right, I have to replace my $n$ by $n-k$ then it gives your formula. Nice job. | |
| May 2, 2017 at 18:12 | comment | added | Abdelmalek Abdesselam | The $n_i$ are constrained to be $\ge 1$ instead of $\ge 0$ so I think my formula is correct. | |
| May 2, 2017 at 16:51 | comment | added | Bazin | About the penultimate equality: I believe that the sum should be replaced by $\sum_{1\le k\le n} 2^k\binom{n+k-1}{k-1}$, which increases geometrically wrt $n$ anyway. | |
| Apr 28, 2017 at 19:57 | history | answered | Abdelmalek Abdesselam | CC BY-SA 3.0 |