Timeline for Fourier transform that is almost a brick wall - but why?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Apr 28, 2017 at 22:10 | comment | added | Christian Remling | This reminds me of something I read the other day (don't remember now where or who wrote it), where the author made the point that, contrary to what most mathematicians think, one cannot use arbitrary symbols for mathematical quantities. For example, while one may well call a function $f(x)$, denoting it by $x(f)$ instead immediately makes any further analysis impossible. | |
| Apr 28, 2017 at 21:00 | answer | added | Carlo Beenakker | timeline score: 6 | |
| Apr 28, 2017 at 18:03 | comment | added | Nicki | I mean $g^{-3/2}$. $f$ stands for frequency, $H$ for the transform | |
| Apr 28, 2017 at 17:54 | comment | added | Willie Wong | In the question, do you really mean $g^{-3/2}$ or $g^{-3}$? | |
| Apr 28, 2017 at 17:52 | comment | added | Willie Wong | I think the OP is using $f$ for the variables many of us will normally call $\xi$, and $H$ the function many of us will write $\hat{h}$. | |
| S Apr 28, 2017 at 17:38 | history | suggested | the_fox | CC BY-SA 3.0 |
improved formatting
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| Apr 28, 2017 at 17:31 | review | First posts | |||
| Apr 28, 2017 at 17:38 | |||||
| Apr 28, 2017 at 17:26 | comment | added | Nik Weaver | What is $f$? What is $H(f)$? | |
| Apr 28, 2017 at 17:25 | review | Suggested edits | |||
| S Apr 28, 2017 at 17:38 | |||||
| Apr 28, 2017 at 17:24 | comment | added | Sylvain JULIEN | There may be a link with curvature, as the curvature of a $ C^{2} $ function $ f $ at $ x $ is expressed as $ f''(x).(1+f'(x)^2)^{-3/2} $, if I remember correctly. | |
| Apr 28, 2017 at 17:19 | history | asked | Nicki | CC BY-SA 3.0 |