Timeline for Counting Bipartitions
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 28, 2017 at 6:19 | vote | accept | Steven Spallone | ||
| Apr 27, 2017 at 11:23 | comment | added | Douglas Zare | I think the total is $\Theta(\sqrt{n})$ times the middle term. | |
| Apr 27, 2017 at 11:01 | comment | added | Janne Kokkala | Using the full sum $p_2(n) = \sigma_{a+b=n}p(a)p(b)$ might give us an approximation for $p_2(n)/p(n)$, but I don't know if there's a reasonable or elegant way to do that. | |
| Apr 27, 2017 at 10:56 | history | answered | Janne Kokkala | CC BY-SA 3.0 |