Timeline for Cobordism/bordism group based on orbifolds with corners
Current License: CC BY-SA 3.0
11 events
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| Apr 27, 2017 at 13:21 | comment | added | Thomas Rot | Also interesting to note is that a point is nullbordant if one admits orbifolds. | |
| Apr 27, 2017 at 13:19 | comment | added | Thomas Rot | The problem i was thinking of is that the boundary of a manifold with corners is not a manifold with corners. This is already not true for the model of the positive quadrant in $R^n$. Or think of a space homeomorphic to a disc, but with one corner. I don't see how orbifolds solve this. | |
| Apr 27, 2017 at 12:16 | history | edited | David White | CC BY-SA 3.0 |
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| Apr 27, 2017 at 11:00 | answer | added | Nicholas Kuhn | timeline score: 2 | |
| Apr 27, 2017 at 10:58 | history | edited | Hao Yu | CC BY-SA 3.0 |
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| Apr 27, 2017 at 10:36 | review | Close votes | |||
| Apr 27, 2017 at 19:29 | |||||
| Apr 27, 2017 at 9:48 | comment | added | Hao Yu | The orbifold with corners is well formed,similar to the simplexes. Any point $x$ lies in exactly $n$ faces, where $n$ is the codimension of $x$, where "codimension" is the number of zero coordinates in any chart containing $x$ | |
| Apr 27, 2017 at 9:43 | comment | added | Hao Yu | Does "oriented" condition avoid the issue you mentioned?Why does not it square zero, can you give an example? | |
| Apr 27, 2017 at 9:28 | history | edited | Hao Yu | CC BY-SA 3.0 |
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| Apr 27, 2017 at 9:08 | comment | added | Thomas Rot | Why does the boundary square to zero if one allows corners? You probably want to add compactness somewhere as well, otherwise every orbifold bords | |
| Apr 27, 2017 at 8:50 | history | asked | Hao Yu | CC BY-SA 3.0 |