Timeline for The uniqueness of a $K$-fixed vector in a spinor representation
Current License: CC BY-SA 3.0
5 events
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Apr 25, 2017 at 17:37 | vote | accept | Ninnat Dangniam | ||
Apr 25, 2017 at 3:13 | comment | added | Victor Protsak | Yes, although to be completely precise, you should rephrase to "subspace consisting of $K$-fixed vectors means that it is actually a trivial representation". I was glad to have been able to help. | |
Apr 25, 2017 at 2:42 | comment | added | Ninnat Dangniam | Thank you. I see. The trivial $U(n)$-representation (the vacuum) and the $U(n)$-representation on the highest exterior power are not the same, and a subspace being $K$-fixed means that it is actually a trivial representation and not merely any 1-dimensional representation. Is that correct? | |
Apr 25, 2017 at 2:17 | history | edited | Victor Protsak | CC BY-SA 3.0 |
Expanded
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Apr 25, 2017 at 1:40 | history | answered | Victor Protsak | CC BY-SA 3.0 |