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Timeline for Finite Topology vs sigma Field

Current License: CC BY-SA 4.0

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Dec 17, 2018 at 10:35 comment added Pietro Majer Yes, of course, but $\mathcal{R}$ was already assumed to be an equivalence relation, in particular symmetric. But maybe the double implication is more clear. Done. Thank you
Dec 17, 2018 at 10:35 history edited Pietro Majer CC BY-SA 4.0
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Dec 17, 2018 at 3:28 comment added LSpice Don’t you want your definition of $s{\mathcal R}t$ to have a biconditional, as in $s \in A \iff t \in A$?
Jun 2, 2010 at 20:25 comment added Pietro Majer Note that to define the family of sets A<sub>s,t</sub> I needed a countable choice; I suppose it's unavoidable in order to prove the statement.
Jun 2, 2010 at 20:18 history edited Pietro Majer CC BY-SA 2.5
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Jun 2, 2010 at 8:51 history edited Pietro Majer CC BY-SA 2.5
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Jun 2, 2010 at 8:46 history edited Pietro Majer CC BY-SA 2.5
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Jun 2, 2010 at 8:39 history answered Pietro Majer CC BY-SA 2.5