Timeline for "Riemannian" collar theorem
Current License: CC BY-SA 3.0
12 events
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Apr 20, 2017 at 14:25 | comment | added | Neal | Wouldn't a family with a singularity degenerating to nontransverse intersection provide a counterexample? For example, a family of "teardrop" domains in the plane, where the teardrop angle goes to zero. | |
Apr 20, 2017 at 13:26 | comment | added | Math101 | @ThomasRot Yes, indeed. I forgot to put the assumption. Also by a universal constant, I meant a constant independent of the family of manifolds under consideration. | |
Apr 20, 2017 at 13:21 | history | edited | Math101 | CC BY-SA 3.0 |
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Apr 20, 2017 at 13:02 | comment | added | Thomas Rot | you probably want to mumble compact if you want a universal constant for one manifold. | |
Apr 20, 2017 at 12:54 | history | edited | Math101 | CC BY-SA 3.0 |
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Apr 20, 2017 at 12:21 | history | edited | Math101 | CC BY-SA 3.0 |
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Apr 20, 2017 at 12:15 | comment | added | Math101 | @MikeMiller thanks for your remark. I agree that the question was very ambiguous. Please see the edited version. | |
Apr 20, 2017 at 12:14 | history | edited | Math101 | CC BY-SA 3.0 |
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Apr 20, 2017 at 12:08 | history | edited | Math101 | CC BY-SA 3.0 |
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Apr 20, 2017 at 11:33 | comment | added | mme | It's not super clear to me what a collar neighborhood theorem means here. Does the unit square have a collar neighborhood? (Certainly I can't see the corner singularities on the interior.) One thing that is clearly true is that each smooth face has a collar neighborhood (this is obvious for the square). | |
Apr 20, 2017 at 11:03 | comment | added | ಠ_ಠ | I'm no expert, but there's a collar neighbourhood theorem for topological manifolds. Might be worth looking at the proof to see if you can adapt their ideas. | |
Apr 20, 2017 at 7:45 | history | asked | Math101 | CC BY-SA 3.0 |