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Dec 28, 2017 at 9:41 comment added user541686 Easy counterexample: $6 = 2 \times 3$ but $6$ does not divide $2$ or $3$...
Feb 7, 2014 at 18:40 comment added Malik Younsi @MartinBrandenburg : What does it mean for an assumption to be incorrect or correct?
May 9, 2011 at 2:15 comment added roy smith i was never able to eradicate this mistake, even by my best students, in spite of naming it the prime divisibility property.
Oct 5, 2010 at 8:23 comment added Martin Brandenburg the correct assumption is $gcd(a,b)=1$.
Jun 1, 2010 at 23:52 history answered Malik Younsi CC BY-SA 2.5