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Apr 20, 2017 at 6:32 history edited Paul Bryan CC BY-SA 3.0
Added link to answer to negative alpha case
Apr 20, 2017 at 6:21 history edited Paul Bryan CC BY-SA 3.0
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Apr 20, 2017 at 6:19 comment added Paul Bryan Yes. Sorry! Carried an extra two.
Apr 19, 2017 at 9:49 comment added user102027 However your $u_2$ is not a subsolution, I think.
Apr 19, 2017 at 2:27 comment added Paul Bryan The solution is not greater than the subsolution! $0 \geq -1/2x + x^2$ is not true for sufficiently large $x$. That's why it's a counter example. In other words, your claim is false for $\alpha < 0$.
Apr 19, 2017 at 1:59 comment added Paul Bryan I updated the answer with a counter example.
Apr 19, 2017 at 1:59 history edited Paul Bryan CC BY-SA 3.0
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Apr 19, 2017 at 0:55 history answered Paul Bryan CC BY-SA 3.0