Timeline for Can an amenable group have a weak mixing unitary representation without almost invariant vectors?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Apr 25, 2017 at 2:15 | vote | accept | Vladimir | ||
| Apr 18, 2017 at 10:42 | comment | added | Andreas Thom | You are right, I deleted this as it was nonsense. | |
| Apr 18, 2017 at 9:01 | comment | added | YCor | Yes, with $G=\mathbf{Z}$. Just split the regular representation $\ell^2(\mathbf{Z})$ as $H_+\oplus H_-$ where $H_-$ corresponds to the part of the spectrum with negative real part. Then $H_-$ is your representation. Equivalently, consider $U_-$, the subset of the unit complex circle with negative real part and Lebesgue meausre, and consider the unitary operator of $L^2(U_-)$ given by $f\mapsto (z\mapsto zf(z))$. | |
| Apr 18, 2017 at 8:39 | answer | added | Andreas Thom | timeline score: 5 | |
| Apr 18, 2017 at 8:27 | history | edited | Andreas Thom | CC BY-SA 3.0 |
added 6 characters in body
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| S Apr 18, 2017 at 8:15 | history | suggested | Martin Sleziak |
added (amenability) and (mixing) tags
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| Apr 18, 2017 at 7:03 | review | Suggested edits | |||
| S Apr 18, 2017 at 8:15 | |||||
| Apr 18, 2017 at 5:51 | history | asked | Vladimir | CC BY-SA 3.0 |