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Apr 17, 2017 at 16:04 comment added Mohan Take $E$ to be the trivial bundle, $\mathcal{O}_X^n$.
Apr 17, 2017 at 16:00 comment added user43198 @Mohan meaning, are there examples when $E$ is not simple but gives a positive answer to the question.
Apr 17, 2017 at 15:59 comment added Mohan What do you mean?
Apr 17, 2017 at 15:58 comment added user43198 @Mohan Thanks, is there any other possibilities?
Apr 17, 2017 at 15:55 comment added Mohan For a simple bundle (for example, stable) $E$, $H^0(\mathcal{E}nd(E))$ is just the scalars, so your condition would be trivially satisfied and you have $C_x=N_x=\mathcal{E}nd(E)_x$.
Apr 17, 2017 at 15:14 history asked user43198 CC BY-SA 3.0