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Apr 22, 2017 at 15:47 history bounty ended CommunityBot
Apr 17, 2017 at 14:12 history edited Max Alekseyev CC BY-SA 3.0
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Apr 17, 2017 at 14:11 comment added Max Alekseyev @KevinSmith: You are correct, there is no cancellation of the highest-order term under these bounds. I've removed the misleading statement from my answer.
Apr 17, 2017 at 12:58 comment added Kevin Smith Thank you for your answer Max - this is a nice way to show that $\sum_{(a,q)=1}a a^*\sim Cq^2\varphi(q)$ for a constant $1/6\leq C\leq 1/3$. Perhaps I am missing something here but, even if $C=1/4$, this establishes only that $S(X)=o(X^{2})$ right? Of course one gets $O(X^{1+\epsilon})$ under the assumption of independence, but that is the reason behind expecting such cancellation (also that numerical data suggests the asymptotic is actually $\sim X/2$).
Apr 17, 2017 at 12:32 history edited Max Alekseyev CC BY-SA 3.0
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Apr 17, 2017 at 12:16 history edited Max Alekseyev CC BY-SA 3.0
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Apr 17, 2017 at 12:07 history edited Max Alekseyev CC BY-SA 3.0
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Apr 17, 2017 at 5:24 history answered Max Alekseyev CC BY-SA 3.0