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Apr 17, 2017 at 1:33 comment added Joel David Hamkins @WłodzimierzHolsztyński Thanks for the edit, even though you haven't said it exactly as I would have.
Apr 16, 2017 at 20:51 history edited Włodzimierz Holsztyński CC BY-SA 3.0
typo
Apr 16, 2017 at 20:42 history edited Włodzimierz Holsztyński CC BY-SA 3.0
formatting typo.
Apr 16, 2017 at 20:34 comment added Włodzimierz Holsztyński Thank you. Now I have your intended meaning, and by now it was not difficult to follow it.
Apr 16, 2017 at 20:20 comment added Joel David Hamkins No, you've misunderstood @WłodzimierzHolsztyński. My hypergraphs allow, in addition to those finite edges, any collection of infinite edges. There are $2^{\aleph_0}$ many infinite edges, and so there are $2^{2^{\aleph_0}}$ many ways to form a hypergraph using them.
Apr 16, 2017 at 20:07 comment added Włodzimierz Holsztyński ? -- The edges of ALL hypergraphs from the collection belotg to a countable family, namely $\ \{1\ldots n\} :n\in\mathbb N\}.\ $ Thus your collection has cardinality $2^\aleph_0,\ $ which smaller than required. Am I wrong? *** I am sure that I misinterpreted your answer. Perhaps your answer is more involved. ?
Apr 16, 2017 at 16:53 vote accept Dominic van der Zypen
Apr 16, 2017 at 11:15 history answered Joel David Hamkins CC BY-SA 3.0