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Apr 14, 2017 at 9:24 comment added Derek Holt @AlirezaAbdollahi That is not true, the dihedral group of order $16$ has a maximal abelian subgroup of order $4$ that is not normal.
Apr 14, 2017 at 6:44 comment added Maryam @Alireza, I think the converse of your assertion is correct. I mean, every maximal normal abelian subgroups are maximal abelian.
Apr 14, 2017 at 3:27 comment added Alireza Abdollahi @Maryam The condition ``$x$ normalize $A$" is superfluous, since in nilpotent groups maximal abelian subgroups are normal.
S Apr 13, 2017 at 15:04 history suggested maryam CC BY-SA 3.0
a quantifier is added
Apr 13, 2017 at 13:55 review Suggested edits
S Apr 13, 2017 at 15:04
Apr 13, 2017 at 11:50 comment added Derek Holt Assuming that the missing quantifier is "there exists", another example is the group of upper unitriangular matrices in ${\rm GL}(n,p)$, which does not have maximal class for $n>2$ (although the subgroup $\langle x,A \rangle$ has maximal class).
Apr 13, 2017 at 10:23 history asked Maryam CC BY-SA 3.0