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Apr 14, 2017 at 1:21 comment added Francois Ziegler @OwenKING Then this $f$ is barely not in $L^p$ ($\int_{\|x\|\leqslant r}|f|^p\simeq\log r$), so it's no longer a counterexample.
Apr 14, 2017 at 0:07 comment added OwenKING what about p=2d/d+1?
Apr 13, 2017 at 5:36 history answered Francois Ziegler CC BY-SA 3.0