Timeline for When the longest element of Weyl group is rational?
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
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Apr 11, 2017 at 20:54 | vote | accept | user148212 | ||
Apr 11, 2017 at 20:26 | comment | added | Jay Taylor | The point here is that $x$ is unique up to right multiplication by elements of $T_0$. | |
Apr 11, 2017 at 20:26 | history | edited | Jay Taylor | CC BY-SA 3.0 |
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Apr 11, 2017 at 19:54 | comment | added | Jay Taylor | Yes, one can already see this from the first part of the answer. I'll update the answer to make it clearer. | |
Apr 11, 2017 at 15:53 | comment | added | user148212 | Thank you. Does this property actually only depends on $T$, i.e. is it possible that there are $x$ and $y$ such that ${^xT_0}={^yT_0}$ but $x^{-1}F(x)$ represents an element in the centraliser while $y^{-1}F(y)$ does not? | |
Apr 11, 2017 at 13:55 | history | edited | Jay Taylor | CC BY-SA 3.0 |
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Apr 11, 2017 at 13:33 | history | answered | Jay Taylor | CC BY-SA 3.0 |