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Apr 8, 2017 at 12:54 vote accept user43198
Apr 8, 2017 at 1:22 answer added Igor Rivin timeline score: 2
Apr 8, 2017 at 0:37 comment added Igor Rivin @MarkGrant Are curves complements of hyperplane arrangements? Because they are all $K(\pi, 1)$ So are products, and fiber products thereof, though I am not sure if there is a classification of which of the latter are algebraic...
Apr 7, 2017 at 23:50 answer added Kevin Casto timeline score: 11
Apr 7, 2017 at 17:09 comment added Mark Grant Further to Donu Arapura's comment, perhaps David Chataur's answer to mathoverflow.net/questions/207448/… can be used to show that the only examples are $K(\pi,1)$'s as mentioned by Piotr Achinger.
Apr 7, 2017 at 15:47 comment added Donu Arapura A smooth complex variety has the homotopy type of a finite CW complex. So I doubt you'll find any examples with all homotopy groups torsion free.
Apr 7, 2017 at 12:22 history edited YCor CC BY-SA 3.0
clarified the question
Apr 7, 2017 at 11:35 comment added user43198 @SeanTilson Yes. Consider the scheme as a complex manifold (assuming non-singularity).
Apr 7, 2017 at 10:05 comment added Sean Tilson What do you mean by homotopy group? The ordinary homotopy groups of the complex points?
Apr 7, 2017 at 9:30 comment added Piotr Achinger There are many interesting $K(\pi, 1)$ examples, e.g. certain complements of hyperplane arrangements. I don't know examples with nontrivial torsion-free higher homotopy groups.
Apr 7, 2017 at 8:26 comment added user43198 @PiotrAchinger Could you suggest some reference which deals with examples of non-torsion homotopy groups in the complex topology.
Apr 7, 2017 at 8:07 comment added Piotr Achinger In characteristic $p$, $\pi_q = 0$ for $q>1$ and $\pi_1$ has no $p$-torsion, but that's of course very different from char. $0$ or the complex topology...
Apr 7, 2017 at 7:26 comment added user43198 @JohnPardon Sorry, meant to write affine scheme
Apr 7, 2017 at 7:25 history edited user43198 CC BY-SA 3.0
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Apr 7, 2017 at 7:12 comment added Sam Nead Surely you need more hypotheses to make progress? For example, any open subset of $\mathbb{R}^n$ is an affine manifold (all transition maps are the identity).
Apr 7, 2017 at 6:56 comment added Sam Nead Perhaps what is meant is a manifold where the transition maps are affine? See en.wikipedia.org/wiki/Affine_manifold
Apr 7, 2017 at 2:18 review Close votes
Apr 7, 2017 at 7:45
Apr 7, 2017 at 2:03 comment added John Pardon Could you clarify what you mean by "affine space"?
Apr 7, 2017 at 1:27 history asked user43198 CC BY-SA 3.0