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Jun 21, 2017 at 20:15 vote accept SKM
Apr 5, 2017 at 5:16 comment added Gerhard Paseman It may be doing the same thing, but in a different way, like multiplication with Roman numerals instead of Arabic. I think they are different but similar because they take different inputs but do a similar job. Until I know what "same" or "alike enough" means, I am going to be cautious and not say they are the same. Gerhard "We Are Not All One" Paseman, 2017.04.04.
Apr 5, 2017 at 3:48 comment added SKM In my question $f^{-1}$ is doing the same thing that is given a symbolic sequence, it is mapping it to a same point. I am confused if $f^{-1}$ which is called as the inverse map or inverse image of the map $f()$ is the same thing as $S^{-1}$ or not because $f^{-1}$ seems to be doing the same thing as $S^{-1}$. Thank you for your feedback.
Apr 5, 2017 at 3:42 comment added SKM $f^{-1}$ is used to encode a symbol string into a real number using the reverse interval mapping, $x \mapsto f^{-1}(0,x)$. If you may kindly see the pdf document in the link web.math.rochester.edu/people/faculty/edummit/docs/… , on Pg13, using an example of quadratic map there is an equivalence between shift map and the quadratic map. Given a symbol string $S(x) = (d_0,d_1,...)$ we can construct $x$ and on pg 14 last line the document says that using $S^{-1}$ is the map that maps the sequence to a single point.
Apr 4, 2017 at 18:53 comment added Gerhard Paseman Every time I see f inverse in your post, it seems to take a symbol or symbol string and a real number or set of real numbers as input. Does S inverse take a real number as input? Gerhard "Let's Get Real Basic Here" Paseman, 2017.04.04.
Apr 4, 2017 at 18:45 comment added SKM In my question i have mentioned that $S^{-1}$ is function from: $\Sigma_2 \rightarrow R$. So, $f^{-1}$ is not the same as $S^{-1}$? By substituting $f(.)$ by $\sigma(.)$ Since the dynamics of the chaotic orbit is studied by the shift map, so by substitute I meant can we replace and use $f(.)$ by $\sigma(.)$ as the symbolic dynamics are obtained directly from $f(.)$ and $\sigma(.)$ is the shift map.
Apr 4, 2017 at 18:27 comment added Gerhard Paseman The intuition is that (from a certain perspective) the map f behaves a lot like the shift map, especially if you look at (technically a modification of) f as just mapping symbols. Conjugate points should behave the same way, or very similarly, under this blurry view of f. I think an expert should weigh in on your questions, as I have not worked through the subject. Gerhard "Definitely Not A Dynamics Expert" Paseman, 2017.04.04.
Apr 4, 2017 at 18:21 comment added Gerhard Paseman (1) from context, I infer the difference since the inverses start from different domains. Actually, you do not give me S inverse, so I am guessing based on your report. (2) I don't know if it safe since I am unsure what substitute means. For me, a gun is safe only if it is kept away from all ammunition. (3) I don't recall conjugacy well enough to trust my explanation. The intuition though should be that it is a way to determine how similar things are. In group Theory, conjugate elements have the same order, for example. Gerhard "Analogies Are Much Like Guns" Paseman, 2017.04.04.
Apr 4, 2017 at 18:09 comment added Gerhard Paseman I will look at your other question, but I no longer use an account there, so I will not respond there. Gerhard "It's A Long Boring Story" Paseman, 2017.04.04.
Apr 4, 2017 at 17:11 comment added SKM (2) Based on your explanation on the purpose of symbolic dynamics, is it safe to say that the chaotic map, $f(.)$ can be substituted by $\sigma(.)$ and the output of $\sigma(.)$ map are the symbols. (3) what does conjugacy tell us and how is it useful? Can you please explain these and also take a glance at my new Question math.stackexchange.com/questions/2216318/… that is in continuation to this one?
Apr 4, 2017 at 17:09 comment added SKM thank you for your reply. However some points are still unclear because of some technical terms. Could you please clarify the following?(1) A chaotic sequence can be obtained from a symbolic sequence through inverse operation of $f^{-1}$. Since, it is an operation from symbolic space to real numbers, so I thought it is the same thing as $S^{-1}$ which is also an operation from symbols to real numbers. But you say that these two are different. Why?
Apr 4, 2017 at 15:47 history edited Gerhard Paseman CC BY-SA 3.0
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Apr 4, 2017 at 15:41 history edited Gerhard Paseman CC BY-SA 3.0
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Apr 4, 2017 at 15:35 history answered Gerhard Paseman CC BY-SA 3.0