Timeline for Algebraic independence in polynomial rings over $\mathbb{Z}_n$
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Apr 4, 2017 at 4:22 | comment | added | darij grinberg | This holds over any nontrivial commutative ring. It is a particular case of Theorem 2 in my post mathoverflow.net/a/144625 (indeed, it is the case when $C' = B $). | |
| Apr 3, 2017 at 22:54 | answer | added | Gro-Tsen | timeline score: 1 | |
| Apr 3, 2017 at 22:45 | history | edited | Amr | CC BY-SA 3.0 |
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| Apr 3, 2017 at 22:41 | comment | added | Amr | @AxelBoldt Thank you a lot. I formalized my intuition in an incorrect way. I will modify my question | |
| Apr 3, 2017 at 22:39 | comment | added | Axel Boldt | Do you really want to consider $\sqrt{2}$ and $\sqrt{3}$ to be algebraically independent over $\Bbb{Q}$? I don't think that's the standard definition. | |
| Apr 3, 2017 at 22:31 | comment | added | Amr | @YCor I mean $\mathbb{Z}/n\mathbb{Z}$ | |
| Apr 3, 2017 at 22:30 | history | edited | Amr | CC BY-SA 3.0 |
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| Apr 3, 2017 at 22:19 | comment | added | YCor | By $\mathbb{Z}_n$, do you mean the projective limit (over $k$) of $\mathbb{Z}/n^k\mathbb{Z}$, or $\mathbb{Z}/n\mathbb{Z}$? | |
| Apr 3, 2017 at 21:36 | history | asked | Amr | CC BY-SA 3.0 |