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Apr 3, 2017 at 20:45 history edited Francois Ziegler CC BY-SA 3.0
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Apr 3, 2017 at 14:35 comment added Francois Ziegler @user135626 Rather the opposite: if $\mu, \nu$ have common denominator $N>1$ (e.g. $\mu=0$, $\smash{\nu=\frac12}$), then $\smash{\int_0^b e^{i(\nu-\mu)\phi}d\phi=0}$ generally requires $b$ to be a multiple of $2N\pi$, not just $2\pi$, i.e. you must expand the domain to an $N$-fold cover of the circle.
Apr 3, 2017 at 11:57 comment added user135626 If we could ignore or avoid the angular multi-valuedness for a moment (e.g. by limiting the chosen domains of $\phi$ in practice), would the product itself be orthogonal for different values of $v$ when $v=M/N$?
Apr 3, 2017 at 5:28 history edited Francois Ziegler CC BY-SA 3.0
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Apr 3, 2017 at 5:00 history answered Francois Ziegler CC BY-SA 3.0