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Apr 1, 2017 at 20:23 vote accept Neil Epstein
Apr 1, 2017 at 6:48 answer added YCor timeline score: 12
Apr 1, 2017 at 4:40 comment added R. van Dobben de Bruyn My previous answer was wrong (thanks to @Pace Nielsen for pointing that out). I will leave with the following remark: by Krull's intersection theorem, it suffices to show that for each $n$, there exists some countable intersection landing in $\mathfrak m^n$. Remarkably, this does not immediately follow from the fact that $R/\mathfrak m^n$ is Artinian, because intersections do not behave well with respect to quotients (even finite intersections don't).
Mar 31, 2017 at 17:01 history asked Neil Epstein CC BY-SA 3.0