Timeline for Is every singular foliation induced by a Lie algebroid?
Current License: CC BY-SA 4.0
13 events
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| May 10, 2023 at 20:59 | comment | added | LSpice | I updated the rotted links, except for the last one, which the Wayback Machine didn't save while it was up. Do you remember the target? | |
| May 10, 2023 at 20:59 | history | edited | LSpice | CC BY-SA 4.0 |
Names of links, and Wayback'ing links, while this is on the front page
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| Mar 27, 2017 at 15:46 | history | edited | Tsemo Aristide | CC BY-SA 3.0 |
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| Mar 27, 2017 at 14:26 | comment | added | Tsemo Aristide | In fact it is a conjecture of Androulidakis and M. Zambon see Lavau thesis p.65 | |
| Mar 27, 2017 at 14:25 | history | edited | Tsemo Aristide | CC BY-SA 3.0 |
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| Mar 27, 2017 at 12:22 | comment | added | Ervin | Can you give me a reference of Skandalis' conjecture? | |
| Mar 27, 2017 at 11:55 | history | edited | Tsemo Aristide | CC BY-SA 3.0 |
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| Mar 27, 2017 at 11:32 | history | edited | Tsemo Aristide | CC BY-SA 3.0 |
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| Mar 27, 2017 at 9:57 | comment | added | Ervin | If the foliation is almost regular, then there is a well defined notion of Holonomy groupoid of it. For example, the construction fails for the foliation on $\mathbb R ^3 $ given by the spheres centered at the origin. (however, this foliation is indeed given by a Lie algebroid because there is a Poisson structure on $\mathbb R ^3 $ which induces that foliation) | |
| Mar 27, 2017 at 9:42 | comment | added | Tsemo Aristide | You may prefer the first reference for the definition of the associated Lie groupoid | |
| Mar 27, 2017 at 9:42 | history | edited | Tsemo Aristide | CC BY-SA 3.0 |
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| Mar 27, 2017 at 9:26 | comment | added | Ervin | I have two comments. 1) In the article you cited, by singular foliation they mean what I call a Stefan-Sussman singular foliation. My definition seems to be more general, and in fact my first question asks precisely if the two definitions are equivalent. 2) I didn't read the whole article, but it seems to me that they associate to every Stefan-Sussman singular foliation a topological groupoid, which is not always Lie. For a topological groupoid, we don't have a well defined notion of Lie algebroid associated to the groupoid. | |
| Mar 27, 2017 at 9:15 | history | answered | Tsemo Aristide | CC BY-SA 3.0 |