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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Mar 26, 2017 at 6:08 comment added R. van Dobben de Bruyn @YCor: ah, very good! I guess I was tacitly assuming $\operatorname{char}(k) = 0$, because that was a running assumption in the original post.
Mar 26, 2017 at 2:02 comment added Lubin “Almost never”. Exactly the words I used in the blurb advertising my talk at Brown Wednesday last.
Mar 26, 2017 at 1:17 comment added YCor In the first example you have to assume $k$ not of char 2 since otherwise $x^2+1$ is a square and indeed in this case there is an extension of the automorphism.
Mar 25, 2017 at 22:45 comment added user237522 Nice answer, thanks! also thanks to @YCor for all his nice counter-examples (one of his counter-examples appears in the answer).
Mar 25, 2017 at 22:04 vote accept user237522
Mar 25, 2017 at 21:52 history answered R. van Dobben de Bruyn CC BY-SA 3.0