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Aug 21, 2019 at 15:47 comment added Zach Teitler However it can be replaced. An affine variety is defined by a multihomogeneous ideal if and only if it's invariant under scaling by a certain product of tori. Then its irreducible components are each, individually, also invariant; check on general points (automatic on intersections). This is a positive answer to question (1). ... If I still feel good about this idea in a few days, and if I remember, I'll update my answer above. If you're reading this comment in the year 2099, I forgot...
Aug 21, 2019 at 15:41 comment added Zach Teitler I don't know what I was thinking in part (1). The irreducible set is contained in at least one irreducible component of $V$. But I don't know why it can't intersect other irreducible components. So, just containing one point of $V_i$ doesn't imply containment in $V_i$. The answer above is bogus. Sorry.
Mar 19, 2017 at 21:22 vote accept Johnny T.
Mar 19, 2017 at 20:22 history answered Zach Teitler CC BY-SA 3.0