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Mar 19, 2017 at 9:51 answer added Jan-Christoph Schlage-Puchta timeline score: 3
Mar 18, 2017 at 17:49 comment added GH from MO Well, if $\alpha_1=1$, then for any choice of $m_2,\dots,m_N$ there is at most one good choice of $m_1$, so in this case $f(N)\leq (2N+1)^{N-1}$. This is still trivial, of course.
Mar 18, 2017 at 17:38 history edited Izaak Meckler CC BY-SA 3.0
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Mar 18, 2017 at 16:51 comment added GH from MO Interesting question, but you probably want to specify it more, otherwise one can say that $f(N)\leq(2N+1)^N$ is a trivial upper bound.
Mar 18, 2017 at 3:37 history edited Izaak Meckler CC BY-SA 3.0
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Mar 17, 2017 at 19:18 history asked Izaak Meckler CC BY-SA 3.0