Timeline for Diophantine equation problem
Current License: CC BY-SA 2.5
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 31, 2010 at 3:04 | comment | added | Will Jagy | Hello, Cindy. I have put a ton of related material at: zakuski.math.utsa.edu/~kap/forms.html On Wadim's idea, there should not be a really easy way to produce integral representations with arbitrary $M$ on the right-hand-side, see my answer (and the others) to mathoverflow.net/questions/3596 | |
| May 31, 2010 at 1:17 | vote | accept | MathematicianMummy | ||
| May 31, 2010 at 1:17 | |||||
| May 30, 2010 at 23:43 | comment | added | Wadim Zudilin | Will, in spite of rain outside I have to teach, so no way to get a longer sleep. On my bus way to uni I wrote a general solution of the equation in rational (by intersecting the ellipsoid with the line $x=t(z-1)$, $y=s(z-1)$ for a rational pair of slopes $t,s$) to see that it does not give a simpler way to produce integer solutions. | |
| May 30, 2010 at 22:11 | comment | added | Will Jagy | Hi Wadim, it does give the appearance of homework as stated for the value $1$ on the right hand side. This would be a stretch for a school-child first exposed to "completing the square." I chose to ignore the $1$ and give the merest hint of what happens next. Meanwhile, I think you should go back to bed. Victor Wadimovich depends on you and you need your strength. | |
| May 30, 2010 at 21:44 | comment | added | Wadim Zudilin | Will, I am getting up too early. The quadratics correspond to the Cartan matrix which reminds me about Rogers-Ramanujan identities. Apart from this, the OP sounds like homework. :) | |
| May 30, 2010 at 19:18 | history | answered | Will Jagy | CC BY-SA 2.5 |