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May 31, 2010 at 4:06 vote accept Audrey Kirilova
May 30, 2010 at 21:11 comment added Jonas Meyer And of course in the second example $J$ and the $I_k$'s are prime.
May 30, 2010 at 18:54 comment added Graham Leuschke You can also get each $I_k$ to be prime, generated by (say) the $(k+2)^{th}$ prime integer.
May 30, 2010 at 18:43 history edited Robin Chapman CC BY-SA 2.5
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May 30, 2010 at 18:38 history answered Robin Chapman CC BY-SA 2.5