Timeline for dyadically recursive matrices: Part I
Current License: CC BY-SA 3.0
5 events
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Mar 16, 2017 at 15:42 | vote | accept | T. Amdeberhan | ||
Mar 16, 2017 at 12:18 | history | edited | T. Amdeberhan | CC BY-SA 3.0 |
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Mar 16, 2017 at 9:03 | comment | added | Wolfgang | Interesting to note that the determinant $\det B_n=\prod(b_1\pm\cdots\pm b_n)$ is symmetric in $b_2,...,b_n$, which is not straightforward from the recursions. | |
Mar 16, 2017 at 8:13 | history | edited | Wolfgang | CC BY-SA 3.0 |
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Mar 16, 2017 at 7:58 | history | answered | Wolfgang | CC BY-SA 3.0 |