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Mar 19, 2017 at 15:00 comment added Neil Strickland @user51223 I suggest that you convert your comments into a separate answer.
Mar 19, 2017 at 14:26 comment added user51223 This paper of Madsen also can be helpful projecteuclid.org/download/pdf_1/euclid.pjm/1102868638
Mar 19, 2017 at 14:21 comment added user51223 or if it is $\sigma^2$. For $\sigma^2$ it maps nontrivially under the Hurewicz map $h:\pi_{14}G\to H_{14}(G;\mathbb{Z}/2)$ whereas $\kappa$ maps trivially under $h$. I thought this has to help in answering your question.
Mar 19, 2017 at 14:20 comment added user51223 I comment on the specific question on the kernel of $H_{14}TOP\to H_{14}G$ when restricted to the image of the Hurewicz map $\pi_{14}TOP\to H_{14}TOP$. The space $G/TOP$ at the prime $2$ is a product of EM spaces $K(\mathbb{Z}/2,4n-2)$ and $K(\mathbb{Z}/2,4n)$. So, look at the Serre homotopy exact sequence for $\Omega(G/TOP)\to TOP\to G\to G/TOP\to BTOP\to BG$ which yields $$\pi_{15}G/TOP\to \pi_{14}TOP\to\pi_{14}G\to\pi_{14}G/TOP$$ which reads as $$0\to\pi_{14}TOP\to\mathbb{Z}/2\{\kappa,\sigma^2\}\to\mathbb{Z}/2.$$ Now, I don't now if it is $\kappa$ which lives in $\pi_{14}TOP$ or...
Mar 17, 2017 at 15:48 comment added Denis Nardin @user106191 $TOP=\Omega BTOP$ so you can probably try to study the Serre spectral sequence. See here for details and references.
Mar 17, 2017 at 8:43 comment added user106191 Thanks a lot for your answer! I had a look at Madsen-Milgram already, and it seems to me that they compute the homology $H_*(Q_0S^0)$, i.e. $H_*(G)$, and $H_*(G/TOP)$ and $H_*(BTOP)$. However I don't see anything on $H_*(TOP)$, and I can't think of a way to derive it from the other. The other books go in similar directions, mostly focussing on $H_*(G)$ and $H_*(BTOP)$. Do you have an idea on how I could go about $H_*(TOP)$? (I will edit my question, too.)
Mar 16, 2017 at 7:47 history answered Neil Strickland CC BY-SA 3.0