Timeline for $E_n(\ell^\infty)=SL_n(\ell^\infty)$?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Mar 16, 2017 at 19:39 | history | edited | Luc Guyot | CC BY-SA 3.0 |
$1$ is the natural bound when using one of the initial coefficients as a pivot
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| Mar 15, 2017 at 17:47 | history | edited | Luc Guyot | CC BY-SA 3.0 |
Explains with details why the second observation implies the result
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| Mar 15, 2017 at 6:19 | history | edited | Luc Guyot | CC BY-SA 3.0 |
Fixes bound on the maximum modulus: there are $n!$ terms in the expansion of the determinant, not just $n$.
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| Mar 14, 2017 at 21:36 | comment | added | YCor | Additional remark: in the ultrametric setting the bound $1/\sqrt[n]{n}$ can be replaced by 1, which provides a better bound in that case. | |
| Mar 14, 2017 at 20:43 | history | edited | Luc Guyot | CC BY-SA 3.0 |
Shortens the first sentence for clarity's sake
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| Mar 14, 2017 at 20:30 | comment | added | Luc Guyot | @YCor: Yes, you are right. I edited my answer so that it incorporates your comment. | |
| Mar 14, 2017 at 20:29 | history | edited | Luc Guyot | CC BY-SA 3.0 |
Integrates YCor's comment AND fixes few typos
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| Mar 14, 2017 at 18:13 | comment | added | YCor | The argument seems to work in any normed field, right? | |
| Mar 14, 2017 at 17:48 | history | answered | Luc Guyot | CC BY-SA 3.0 |