Timeline for Non-commutativity of the d'alambert operator acting on the covariant derivative of a scalar field in general relativity
Current License: CC BY-SA 3.0
4 events
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| Mar 15, 2017 at 17:11 | comment | added | AccidentalFourierTransform | Hi @MikeyMike, Im not sure what you mean by quantum mechanics. All I used is standard differential geometry, with no reference to QM. The use of commutators, $[\nabla_\mu,\nabla_\nu]=\nabla_\mu\nabla_\nu-\nabla_\nu,\nabla_\mu$ is very common when discussing the Riemann tensor. It is ordinary, old-school, differential geometry, not quantum mechanics. | |
| Mar 15, 2017 at 17:03 | comment | added | Nikey Mike | Thanks, interesting approach from quantum mechanics as operators. I have seen that it works also if we take into account that $\nabla^{\mu}\nabla_{\nu}\phi=\nabla_{\nu}\nabla^{\mu}\phi$ for a scalar field in the first term, the term $\nabla_{\mu}\nabla_{\nu}\nabla^{\mu}\phi$ becomes $\nabla_{\mu}\nabla^{\mu}\nabla_{\nu}\phi$. | |
| Mar 14, 2017 at 17:07 | review | First posts | |||
| Mar 14, 2017 at 17:09 | |||||
| Mar 14, 2017 at 17:04 | history | answered | AccidentalFourierTransform | CC BY-SA 3.0 |