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Timeline for A matrix norm inequality II

Current License: CC BY-SA 3.0

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Mar 17, 2017 at 9:05 comment added M. Lin @AliTaghavi I emailed you a proof of the proposition.
Mar 17, 2017 at 9:05 comment added M. Lin @AliTaghavi sure, for example you can find a unitary matrix $X$ such that $AXB$ is equal to the geometric mean of $A^2$ and $B^2$, usually denoted by $A^2\sharp B^2$.
Mar 15, 2017 at 20:43 comment added Ali Taghavi Are there there matrices $A,B,X$ with $A, B$ are positive and X is unitary such that $AXB$ is Hermitian but $AB \neq BA$?
Mar 15, 2017 at 20:31 comment added Ali Taghavi Does your argument work in arbitrary C* algebra?
Mar 15, 2017 at 20:24 comment added Ali Taghavi Very interesting proposition: I am thinking to a proof, in particular the case that X is unitary. Did you wrote your proof some where(arxive, or some thing like this?)I am thinking for possible motivation for consideration of the assumption $AXB$ is hermitian?I am thinking for some geometric interpretation for the proposition in the unitary case. I am thinking also to the sharpnest of $\kappa (X)$ in your inequality. Very great post!
Mar 13, 2017 at 9:14 vote accept M. Lin
Mar 13, 2017 at 6:07 answer added Ali Taghavi timeline score: 7
Mar 13, 2017 at 5:02 history asked M. Lin CC BY-SA 3.0