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May 23, 2017 at 11:12 comment added user21230 Exactly. The $\cdot ^B$ formula assume we express octonions in shape $a+\iota b$ while for $\cdot ^S$ formula we express them in shape $a+b\iota$ where $a,b \in \mathbb H$. Exchanging quaternion with $\iota$ conjugate quaternion, namely $b\iota=\iota\bar b$. This proves the isomorphism. Now I observed, that this what Gro-Tsen explained below, sorry. Still I prefer to use Greek "jota" or Hebrew letter "jod" for extra element.
Mar 11, 2017 at 12:28 review Low quality posts
Mar 11, 2017 at 12:46
Mar 11, 2017 at 12:13 history answered Simon Henry CC BY-SA 3.0