Timeline for When $\frac{a^2}{b+c}+\frac{b^2}{a+c}+\frac{c^2}{a+b}$ is integer and $a,b,c$ are coprime natural numbers, is there a solution except (183,77,13)?
Current License: CC BY-SA 3.0
17 events
when toggle format | what | by | license | comment | |
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S Mar 11, 2017 at 20:15 | history | suggested | Xam | CC BY-SA 3.0 |
Improved formatting
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Mar 11, 2017 at 19:48 | review | Suggested edits | |||
S Mar 11, 2017 at 20:15 | |||||
Mar 11, 2017 at 5:38 | vote | accept | MAEA2 | ||
Mar 11, 2017 at 5:32 | answer | added | Jeremy Rouse | timeline score: 40 | |
Mar 11, 2017 at 4:49 | history | edited | MAEA2 | CC BY-SA 3.0 |
added 18 characters in body
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Mar 11, 2017 at 4:47 | comment | added | MAEA2 | @T.Amdeberhan Oh thanks! Now, I want to find the other answer which fulfils $a,b,c>1$ | |
Mar 11, 2017 at 4:39 | comment | added | T. Amdeberhan | On the trivial side, $(3,1,1)$ is a solution. | |
Mar 11, 2017 at 3:41 | comment | added | MAEA2 | @KConrad I think $\mathbb{N}=1,2,3,\ldots$. | |
Mar 11, 2017 at 3:31 | history | edited | Gottfried Helms | CC BY-SA 3.0 |
spelling in header
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Mar 11, 2017 at 3:27 | comment | added | KConrad | I guess you don't regard $0$ as a natural number? Otherwise let one of $a, b, c$ be $0$ and the other two be $1$. | |
Mar 11, 2017 at 3:27 | comment | added | JMP | you can edit your own questions if you make a mistake - look just right and down of the vote arrows | |
Mar 11, 2017 at 3:25 | comment | added | MAEA2 | sorry,it's first time I use math over flow. Thanks for approvemenrt! | |
S Mar 11, 2017 at 3:23 | history | suggested | JMP | CC BY-SA 3.0 |
changed formula as per comment by author
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Mar 11, 2017 at 3:22 | review | Suggested edits | |||
S Mar 11, 2017 at 3:23 | |||||
Mar 11, 2017 at 3:12 | comment | added | MAEA2 | sorry, $\frac{a^2}{b+c}+\frac{b^2}{c+a}+\frac{c^2}{a+b}$ is correct | |
Mar 11, 2017 at 3:11 | review | First posts | |||
Mar 11, 2017 at 3:22 | |||||
Mar 11, 2017 at 3:09 | history | asked | MAEA2 | CC BY-SA 3.0 |